A squirrel has x- and y-coordinates ( 1.30 m, 3.60m ) at time t1=0 and coordinates ( 5.20m , -0.300m ) at time

A squirrel has x- and y-coordinates ( 1.30 m, 3.60m ) at time t1=0 and coordinates ( 5.20m , -0.300m ) at time t2= 3.50s


a)For this time interval, find the x-component of the average velocity.


b)For this time interval, find the y-component of the average velocity.


c)Find the magnitude of the average velocity.


d)Find the direction of the average velocity.A squirrel has x- and y-coordinates ( 1.30 m, 3.60m ) at time t1=0 and coordinates ( 5.20m , -0.300m ) at time
average velocity has an easy formula...





x2 - x1


-------


t2 - t1





In this case,





a) vx = (5.2 - 1.3)/(3.5 - 0) = 1.11 m/s


b) vy = (-.3 - 3.6)/(3.5 - 0) = -1.11 m/s


c) v = sqrt(vx^2 + vy^2) = 1.57 m/s


d) tan(theta) = vy/vx, so theta = 45潞 below the positive x-axisA squirrel has x- and y-coordinates ( 1.30 m, 3.60m ) at time t1=0 and coordinates ( 5.20m , -0.300m ) at time
Does the squirrel know about this?
Do your own homework !